Lösung: Q-0015

Licht:
α=arctan(x/y) = 13,5°
d = 0,001m/n = 1,8μm
λ=d sin(α)/n = 140 nm

Elektronen:
W_e = Ue = 9,6E-17 J
p = m v = m$\sqrt{2W_e/m_e}$=1,3E-23 kg m/s
λ=h/p = 5,01 E-11 m

α=arctan(x/y) = 16,2°; 24,7°; 56,7
d = λ/sin(α) = 0,12 nm; 0,18 nm; 0,12nm mit n=2!!!

zurück home inhalt