Lösung: Q-0015

Licht:
α=arctan(x/y) = 13,5°
d = 0,001m/n = 1,8μm
λ=d sin(α)/n = 140 nm

Elektronen:
We = Ue = 9,6E-17 J
p = m v = m 2 W e / m e =1,3E-23 kg m/s
λ=h/p = 5,01 E-11 m

α=arctan(x/y) = 16,2°; 24,7°; 56,7
d = λ/sin(α) = 0,12 nm; 0,18 nm; 0,12nm mit n=2!!!


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