Lösung: A-0042


Aufgabe 1)
a) B 5 11 + n 0 1 W B 5 12 C 6 12 + e 1 0 + ν + γ
b) Δm1 = mB-11 + mn - (mC-12+me) = 0,00362 u = 6 E-30 kg
W1 = Δm c2 = 5,4 E-13 J = 3,4 MeV

Δm2 = mB-12 - (mC-12+me) = 0,014353 u = 2,3883 E-29 kg
W2 = Δm c2 = 2,1 E-12 J = 13,4 MeV

c) dW = 13,4MeV - 13,369 MeV = 0,03716 MeV
v = 2 dW m = 1,14 E8 m/s = 38% von c

Aufgabe 2)
a) N = 1kg / mB-11 = 5,4714 E25

b) W = N (W1 + W2) = 1,47 E14 J

c) t = W/P = 113036 sec = 1,3 d

Aufgabe 3)
a) N0 = 1kg / mB-12 = 5,0136 E25
N(t) = N0 (1/2)t/T1/2 = 6,28 E10

b) t = ln(0,015)/ln(2) * T1/2 = 0,1224 sec


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