Lösung: A-0042

Aufgabe 1)
a)$B_5^{11}+n_0^1-W\to B_5^{12}\to C_6^{12}+e_{-1}^0+\nu +\gamma$
b) Δm₁ = m_B-11 + m_n - (m_C-12+m_e) = 0,00362 u = 6 E-30 kg
W₁ = Δm c² = 5,4 E-13 J = 3,4 MeV

Δm₂ = m_B-12 - (m_C-12+m_e) = 0,014353 u = 2,3883 E-29 kg
W₂ = Δm c² = 2,1 E-12 J = 13,4 MeV

c) dW = 13,4MeV - 13,369 MeV = 0,03716 MeV
v = $\sqrt{\frac{2\mathrm{dW}}{m}}$= 1,14 E8 m/s = 38% von c

Aufgabe 2)
a) N = 1kg / m_B-11 = 5,4714 E25

b) W = N (W₁ + W₂) = 1,47 E14 J

c) t = W/P = 113036 sec = 1,3 d

Aufgabe 3)
a) N₀ = 1kg / m_B-12 = 5,0136 E25
N(t) = N₀ (1/2)^t/T1/2 = 6,28 E10

b) t = ln(0,015)/ln(2) * T_1/2 = 0,1224 sec

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